[Retros] shortest Madrasi PG stalemate ended - Solution

[Nicolas.Dupont at math.univ-lille1.fr]

> A shorter one :

>

> 1.a4 c5 2.a5 c4 3.Ra4 c3 4.Rc4 f5 5.Rxc8 Nc6 6.a6 Qa5 7.Na3 Qxa3

> 8.Nf3 Qd6 9.Nd4 Qxh2 10.Rxh2 f4 11.Rxh7 f3 Madrasi =


Ouarff, it is not dual-free. But according to Popeye, the following
12-variation is correct :

 1.h2-h4 c7-c5   2.h4-h5 c5-c4   3.Rh1-h4 c4-c3   4.Rh4-c4 f7-f5
 5.Rc4*c8 f5-f4   6.Rc8*b8 Qd8-a5   7.Sg1-f3 Qa5*a2   8.Sf3-e5 Qa2*b1
  9.Ra1-a6 f4-f3  10.Ra6-h6 e7-e6  11.Rh6*h7 Sg8-e7  12.h5-h6 Se7-g6

The wrong 11-variation suggests, nevertheless, that  12 might not be the
infimum.

Nicolas.